基于jQuery实现图片的前进与后退功能-Web前端之家

复制代码代码如下:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<title></title> 
<style type="text/css"> 
#mydiv{ position:absolute; width:500px; height:400px; top:50%; left:50%; margin-top:-200px; margin-left:-290px; } 
img{ width:480px; height:380px;} 
</style> 
<script src="jquery-1.9.1.js" type="text/javascript"></script> 
<script src="Jquery1.7.js" type="text/javascript"></script> 
<script type="text/javascript"> 
$(function () { 
var array = [1, 2, 3, 4, 5, 6]; 
var count = 0; 
//后退 
$('#Button1').click(function () { 
if (count > 0) { 
count--; 
$('img').attr('src', 'images/' + array[count] + '.jpg'); 
} 
}) 
//前进 
$('#Button2').click(function () { 
if (count < 5) { 
count++; 
$('img').attr('src', 'images/' + array[count] + '.jpg'); 
} 
}) 
}) 
</script> 
</head> 
<body> 
<div id="mydiv"> 
<table><tr><td><input id="Button1" type="button" value="<" /></td><td><img src="images/1.jpg" /></td><td><input id="Button2" type="button" value=">" /></td></tr></table> 
</div> 
</body> 
</html> 